Free Oracle 1Z0-898 Exam Dumps Questions & Answers

A developer is writing an application with three java Persistence API entities: order, customer, and Address. There is a many-to-one relationship between order and customer, and a one to-many relationship between customer and Address.
Which two Criteria queries will return the orders of all customers who have an address whose value specified by the String parameter postalcode? (Choose two)

• A.String postalCode = . . .
  Criteria Builder cb = . . .
  CriteriaQuery<order> cq = cb.createQuery (Order.class);
  Root <order> order = cq.from(order.class);
  Join <order, Customer> customer = order.join(Order_.customer);
  Root <Order> order = cq.from (Order.class);
  Join <customer, Address> address = customer join (Order_.customer)
  cq.where (cb.equal (address.get(Address_.postalCode), postalCode));
  cq.select (order). Distinct (true);
  // query execution code here
  . . .
• B.String postalCode = ...
  CritetiaBuilder cb = ...
  Root<order> order = cq - from (Order . class) ,
  Join<order, Address> address = order.join(Customer_.addresses);
  cq.where(ct>.equal(address.get(Address_.postalCode), postalCode));
  cq-select(order).distinct(true);
  // query execution code here
  . . .
• C.String postalCode = . . .
  Criteria Builder cb = . . .
  Root <Order> order = cq.from (Order.class);
  order.join (order_. customer).join(Customer_.addresses);
  cq.where (cb.equal (address.get(Address_.postalCode), postalCode));
  cq.select (order). Distinct (true);
  // query execution code here
• D.String postalCode = ...
  CriteriaBuilder cb = ...
  Root<order> order = cq- from (Order . class ) ,
  Join<order, Address> address = order . join (Order_. customer) -join (Customer_.addresses);
  cq.where <cb.equal (address.get(Address_.postalCode) , postalCode) ) ;
  cq.selec:(order).distinct(true);
  // query execution code here
  . . .

A session bean business method throws an exception during execution.
Which two are responsibilities of the Bean Provider when throwing the exception? (Choose two.)

• A.For system errors, when the client is remote through a java.rmi.remoteException that wraps the original exception.
• B.For application exceptions, ensure that the current transaction will commit.
• C.For application exceptions, ensure that ifthe current transaction commits there will be noloss ofdata integrity.
• D.For checked exceptions from which the bean cannot recover, throw an EJBException that wraps the original exception.

Which of the following Criteria query snippets demonstrates the correct way to create and execute strongly typed queries? Assume that cb references an instance of the CriteriaBuilder interface and em references an EntityManager instance.

• A.CriteriaQuery <office> cq = cb.createQuery (Office.class);
  . . .
  TypedQuery<Office> tq = em.ceateQuery (cq) ; L
  1st <office> offices = tq.getResultList ();
• B.CriteriaQuery cq = cb.createQuery (Office.class)
  . . .
  TypedQuery<office> tq = em.createQuery (cq, office.class);
  List <office> offices = tq.getresult ();
• C.CriteriaQuery<office> cq = em.createQuery (cq, office.class);
  . . .
  TypedQuery<Office> tq = em.createQuery (cq);
  List <office> offices = tq.getresult ();
• D.CriteriaQuery <office> cq = cb.createQuery (Office.class);
  . . .
  TypedQuery<Office> tq = em.ceateQuery (cq);
  List<office> Offices = tq.getResultList ();

It a Persistence application locks entity x with a pessimistic lock, which statement is true?

• A.A Persistenceprovider will obtain the lock when the entity is refreshed from the database.
• B.A Persistence provider is not required to support the LockModeType. PESSIMISTIC_WRITE locking type.
• C.Persistence provider can defer obtaining the lock until the next synchronization of an entity to the database.
• D.If a lock cannot be obtained, the Persistence provider must throw an exception.

A developer has created a deep entity class hierarchy with many polymorphic relationships between entitles. Which inheritance strategy, as defined by the inheritanceType enumerated type, will be most performed in this scenario?

• A.Single table-per-class-hierarchy (InheritanceType.SINGLE_TABLE)
• B.Joined-subclass (inheritanceType. JOINED)
• C.Table-per-concrete-class (inheritanceType.TABLE_PER_CLASS)
• D.Polymorphic join table (inheritanceType. POLYMORPHIC_JOIN_TABLE)