Question 76
Given the code fragment:
BiFunction<Integer, Double, Integer> val = (t1, t2) -> t1 + t2; //line n1
//line n2
System.out.println(val.apply(10, 10.5));
What is the result?
Question 77
Given:
And given the code fragment:
Question 78
Given the code fragment:
Stream<Path> files = Files.walk(Paths.get(System.getProperty("user.home")));
files.forEach (fName -> {//line n1
try {
Path aPath = fName.toAbsolutePath();//line n2
System.out.println(fName + ":"
+ Files.readAttributes(aPath, Basic.File.Attributes.class).creationTime
());
} catch (IOException ex) {
ex.printStackTrace();
});
What is the result?
Question 79
The data.doc, data.txt and data.xml files are accessible and contain text.
Given the code fragment:
Stream<Path> paths = Stream.of (Paths. get("data.doc"),
Paths. get("data.txt"),
Paths. get("data.xml"));
paths.filter(s-> s.toString().endWith("txt")).forEach(
s -> {
try {
Files.readAllLines(s)
.stream()
.forEach(System.out::println); //line n1
} catch (IOException e) {
System.out.println("Exception");
}
}
);
What is the result?
Question 80
Given the code fragment:
Which two code fragments can be independently inserted at line n1 to enable the code to print the elements of the array in reverse order?