What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main(){
int i = 1;
if (--i==1) {
cout << i;
} else {
cout << i-1;
}
return 0;
}

• A.It prints: 0
• B.It prints: 1
• C.It prints: -1
• D.It prints: 2

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What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
int x=2, *y;
y = &x;
cout << *y + x;
return 0;
}

• A.It prints: 1
• B.It prints: 4
• C.It prints: 0
• D.It prints: 2

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What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class A {
public :
void print() {
cout << "A ";
}
};
class B {
public :
void print() {
cout << "B ";
}
};
int main() {
B sc[2];
B *bc = (B*)sc;
for (int i=0; i<2;i++)
(bc++)->print();
return 0;
}

• A.It prints: B A
• B.It prints: A B
• C.It prints: A A
• D.It prints: B B

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Name: *

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What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main(){
int i = 1;
if (i==1) {
cout << i;
} else {
cout << i-1;
}
return 0;
}

• A.It prints: 0
• B.It prints: 1
• C.It prints: -1
• D.It prints: 2

Comment: *

Name: *

Email: *

Verification: *

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
namespace myNamespace1
{
int x = 5;
int y = 10;
}
namespace myNamespace2
{
float x = 3.14;
float y = 1.5;
}
int main () {
{
using namespace myNamespace1;
cout << x << " ";
}{
using namespace myNamespace2;
cout << y;
}
return 0;
}

• A.Compilation error
• B.None of these
• C.It prints: 3.14 10
• D.It prints: 5 1.5

Comment: *

Name: *

Email: *

Verification: *