You have two tables as shown in the following image:

You need to analyze the following query. (Line numbers are included for reference only.)

Use the drop-down menus to select the answer choice that completes each statement based on the information presented in the graphic.
NOTE: Each correct selection is worth one point.

Correct Answer:

Explanation

To compare char(5) and nchar(5) an implicit conversion has to take place.
Explicit conversions use the CAST or CONVERT functions, as in line number 6.
References:
https://docs.microsoft.com/en-us/sql/t-sql/data-types/data-type-conversion-database-engine#implicit-and-explicit

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DRAG DROP
Note: This question is part of a series of questions that use the same scenario. For your convenience, the scenario is repeated in each question. Each question presents a different goal and answer choices, but the text of the scenario is exactly the same in each question in this series.
Start of repeated scenario
You have a database that contains the tables shown in the exhibit. (Click the Exhibit button.)

You review the Employee table and make the following observations:
- Every record has a value in the ManagerID except for the Chief Executive Officer (CEO).
- The FirstName and MiddleName columns contain null values for some records.
- The valid values for the Title column are Sales Representative manager, and CEO.
You review the SalesSummary table and make the following observations:
- The ProductCode column contains two parts: The first five digits represent a product code, and the last seven digits represent the unit price. The unit price uses the following pattern: ####.##.
- You observe that for many records, the unit price portion of the ProductCode column contains values.
- The RegionCode column contains NULL for some records.
- Sales data is only recorded for sales representatives.
You are developing a series of reports and procedures to support the business. Details for each report or procedure follow.
Sales Summary report: This report aggregates data by year and quarter. The report must resemble the following table.

Sales Manager report: This report lists each sales manager and the total sales amount for all employees that report to the sales manager.
Sales by Region report: This report lists the total sales amount by employee and by region.
The report must include the following columns: EmployeeCode, MiddleName, LastName,
RegionCode, and SalesAmount. If MiddleName is NULL, FirstName must be displayed. If both FirstName and MiddleName have null values, the world Unknown must be displayed/
If RegionCode is NULL, the word Unknown must be displayed.
Report1: This report joins data from SalesSummary with the Employee table and other tables. You plan to create an object to support Report1. The object has the following requirements:
- be joinable with the SELECT statement that supplies data for the report
- can be used multiple times with the SELECT statement for the report
- be usable only with the SELECT statement for the report
- not be saved as a permanent object
Report2: This report joins data from SalesSummary with the Employee table and other tables.
You plan to create an object to support Report1. The object has the following requirements:
Sales Hierarchy report. This report aggregates rows, creates subtotal rows, and super- aggregates rows over the SalesAmount column in a single result-set. The report uses
SaleYear, SaleQuarter, and SaleMonth as a hierarchy. The result set must not contain a grand total or cross-tabulation aggregate rows.
Current Price Stored Procedure: This stored procedure must return the unit price for a product when a product code is supplied. The unit price must include a dollar sign at the beginning. In addition, the unit price must contain a comma every three digits to the left of the decimal point, and must display two digits to the left of the decimal point. The stored procedure must not throw errors, even if the product code contains invalid data.
End of Repeated Scenario
You are creating the queries for Report1 and Report2.
You need to create the objects necessary to support the queries.
Which object should you use to join the SalesSummary table with the other tables that each report uses? To answer, drag the appropriate objects to the correct reports. each object may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.

Answer <map><m x1="6" x2="230" y1="37" y2="64" ss="0" a="0" /><m x1="4" x2="228" y1="78" y2="98" ss="0" a="0" /><m x1="6" x2="227" y1="115" y2="137" ss="0" a="0" /><m x1="5" x2="230" y1="154" y2="175" ss="0" a="0" /><m x1="4" x2="227" y1="193" y2="214" ss="0" a="0" /><m x1="4" x2="230" y1="231" y2="255" ss="0" a="0" /><m x1="4" x2="230" y1="268" y2="291" ss="0" a="0" /><m x1="3" x2="230" y1="309" y2="330" ss="0" a="0"
/><m x1="452" x2="671" y1="73" y2="96" ss="1" a="0" /><m x1="450" x2="674" y1="101" y2="123" ss="1" a="0" /><c start="7" stop="0" /><c start="0" stop="1" /></map>

Correct Answer:

Explanation:

Box 1: common table expression (CTE)
A common table expression (CTE) can be thought of as a temporary result set that is defined within the execution scope of a single SELECT, INSERT, UPDATE, DELETE, or
CREATE VIEW statement. A CTE is similar to a derived table in that it is not stored as an object and lasts only for the duration of the query. Unlike a derived table, a CTE can be self-referencing and can be referenced multiple times in the same query.
A CTE can be used to:
From Scenario: Report1: This report joins data from SalesSummary with the Employee table and other tables. You plan to create an object to support Report1. The object has the following requirements:
Box 2: view
From scenario: Report2: This report joins data from SalesSummary with the Employee table and other tables.
You plan to create an object to support Report1. The object has the following requirements:
References: https://technet.microsoft.com/en-us/library/ms190766(v=sql.105).aspx

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Note: This question is part of a series of questions that present the same scenario. Each question in the series contains a unique solution that might meet the stated goals. Some question sets might have more than one correct solution, while others might not have a correct solution.
After you answer a question in this section, you will NOT be able to return to it. As a result, these questions will not appear in the review screen.
You create a table named Customer by running the following Transact-SQL statement:

You create a cursor by running the following Transact-SQL statement:

If the credit limit is zero, you must delete the customer record while fetching data.
You need to add the DELETE statement.
Solution: You add the following Transact-SQL statement:

Does the solution meet the goal?

• A.YES
• B.NO

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You are a developing a solution to manage employee training records. You have the following Transact-SQL statement:

You need to create a stored procedure that returns the total number of participants for a specific course.
How should you complete the procedure? To answer, drag the appropriate Transact-SQL segments to the correct locations. Each Transact-SQL segment may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
NOTE: Each correct selection is worth one point.

Correct Answer:

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Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply only to that question.
You have a database that contains tables named Customer_CRMSystem and Customer_HRSystem. Both tables use the following structure:
The tables include the following records:
Customer_CRMSystem

Customer_HRSystem

Records that contain null values for CustomerCode can be uniquely identified by CustomerName.
You need to create a list of all unique customers that appear in either table.
Which Transact-SQL statement should you run?
A：

B：

C:

D:

E:

F：

G:

H:

• A.Option A
• B.Option B
• C.Option C
• D.Option D
• E.Option E
• F.Option F
• G.Option G
• H.Option H

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